A cell phone plan charges $30 per month plus $0.10 per text. Which equation represents the monthly cost C for t texts?
AC = 0.10(30 + t)
BC = 30 + 0.10t
CC = 30t + 0.10
DC = 30.10t
Explanation
📌 Fixed cost = $30 (base monthly charge) Variable cost = $0.10 per text = 0.10t Total: C = 30 + 0.10t
💡 This is a linear equation in slope-intercept form: y = mx + b where m = 0.10 and b = 30.
Question 2 of 10
TEKS 2A-2HEasy Calc Word Diagram
What is the slope of the line shown?
A−1
B1/2
C2
D1
Explanation
📌 slope = rise/run = (3-(-1))/(2-(-2)) = 4/4 = 1
💡 Positive slope → line goes UP from left to right.
Question 3 of 10
TEKS 1A-1GMedium Calc Word
A car rental costs $25 per day plus $0.15 per mile. If the total cost is $70 for one day, how many miles were driven?
A350
B300
C250
D200
Explanation
📌 70 = 25 + 0.15m 45 = 0.15m m = 300 miles
Question 4 of 10
TEKS 5A-5CHard Calc
Solve: 3x+4y=10, 2x−4y=−5
A(1, 2)
B(0, 2.5)
C(2, 1)
D(1, 1.75)
Explanation
📌 Add: 5x=5 → x=1. 3(1)+4y=10 → 4y=7 → y=7/4=1.75
Question 5 of 10
TEKS 5A-5CMedium Calc Word Diagram
The graph shows two lines. What is the solution to the system?
A(0, 1)
B(2, 3)
C(1, 2)
D(3, 0)
Explanation
📌 The solution is where the lines intersect = (1, 2). Verify: y = x + 1 → 2 = 1 + 1 ✓ y = −x + 3 → 2 = −1 + 3 ✓
Question 6 of 10
TEKS 2A-2HMedium Calc Word Diagram
Which line has a negative slope?
ABoth
BNeither
CA
DB
Explanation
📌 Negative slope = line goes DOWN from left to right (↘). Positive slope = line goes UP from left to right (↗). Graph B has negative slope.
Question 7 of 10
TEKS 4A-4CMedium Calc Word Diagram
The scatter plot shows the relationship between hours studied and test scores. What type of correlation is shown?
ANo correlation
BCannot determine
CNegative correlation
DPositive correlation
Explanation
📌 Points trend upward from left to right → positive correlation. As hours studied increases, test score increases. The trend line slopes upward → positive relationship.
Question 8 of 10
TEKS 5A-5CHard Calc Word
Solve: 2x + 3y = 13, 4x − y = 5
A(3, 2)
B(1, 4)
C(4, 1)
D(2, 3)
Explanation
📌 From eq2: y = 4x − 5 Substitute: 2x + 3(4x−5) = 13 → 2x + 12x − 15 = 13 → 14x = 28 → x = 2 y = 4(2) − 5 = 3